FTH0027canonicalv1no_tie (theorem)
/-- [I.L03] No-Tie Lemma: If b₁ · A↑↑(c₁-1) = b₂ · A↑↑(c₂-1) (=: v), and both c₁, c₂ are maximal (¬(A↑↑cᵢ ∣ v)), then c₁ = c₂ and b₁ = b₂. Proof: Suppose c₁ < c₂. Then A↑↑c₁ ∣ A↑↑(c₂-1) (since both are powers of A and c₁ ≤ c₂-1). Hence A↑↑c₁ ∣ v = b₂ · A↑↑(c₂-1). But ¬(A↑↑c₁ ∣ v), contradiction. So c₁ = c₂, then b₁ = b₂. -/
Formalization
Identifiers
Aliases & legacy IDs
no_tieno-tieTauLib.BookI.Coordinates.NoTie::no_tieRelease lines
corpus_v2corpus_v3_workingVersion & History
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