THM0213canonicalv1Radical Primorial 5
rad(M_k) = M_k for k=1..5. Primorial tower is entirely squarefree.
Payload
Radical Primorial 5
rad(M_k) = M_k for k=1..5. Primorial tower is entirely squarefree.
Radical Primorial 5
Summary
rad(M_k) = M_k for k=1..5. Primorial tower is entirely squarefree.
Statement
\label{thm:radical-primorial-5}
$\mathrm{rad}(M_k) = M_k$ for $k = 1, \ldots, 5$. The primorial tower is
entirely squarefree.
\textbf{Lean:} \texttt{radical\_primorial\_5}.\quad
\textbf{Registry:} III.T78.
Proof / Justification
No immediate manuscript proof block was extracted in this pilot run.
Source Context
- Registry source:
book-03.jsonlline 280 - Manuscript source:
2nd-edition/book-iii-categorical-spectrum/02_mainmatter/part10/ch81-additive-conjectures-deep.texlines 365-371
Lean / Formalization Notes
- Formalization:
formalized - Module:
TauLib.BookIII.Arithmetic.ABCDeep - Name:
radical_primorial_5
Dependencies
- Canonical: III.D97
Related Results
Generated by later projection phases.
Related Publications
Generated by later projection phases.
Revision Notes
- 2026-04-24: Initial pilot migration.
Identifiers
Aliases & legacy IDs
III.T78radical-primorial-5thm:radical-primorial-5Release lines
corpus_v3_workingcorpus_v2Relations
Formalized by (1)
Appears in (1)
Downstream uses (computed) (2)
Items in the corpus that reference this one via load-bearing relations. Computed from the full corpus-v3 graph at build time.
Sources
Version & History
Status disclaimer
A Corpus Item page reports the program's current internal record for this item. It does not imply external verification, scientific consensus, or final proof unless explicitly stated. Read it together with its dependencies, formalization status, and the program's overall stance.