THM0015canonicalv1Tetration Algebraic Degradation
Tetration is algebraically degraded: non-commutative (2^^3 != 3^^2), non-associative ((2^^2)^^2 != 2^^(2^^2)), no left identity >= 2. This is the algebraic obstruction to canonicality at the 4th operation level.
Payload
Tetration Algebraic Degradation
Tetration is algebraically degraded: non-commutative (2^^3 != 3^^2), non-associative ((2^^2)^^2 != 2^^(2^^2)), no left identity >= 2. This is the algebraic obstruction to canonicality at the 4th operation level.
Tetration Algebraic Degradation
Summary
Tetration is algebraically degraded: non-commutative (2^^3 != 3^^2), non-associative ((2^^2)^^2 != 2^^(2^^2)), no left identity >= 2. This is the algebraic obstruction to canonicality at the 4th operation level.
Statement
%
\label{thm:tetration-degraded}
Tetration fails all three algebraic canonicality conditions:
\begin{enumerate}
\item \textbf{Non-commutative:}
${}^{\underline{3}}\underline{2} = \underline{16}
\neq \underline{9} = {}^{\underline{2}}\underline{3}$.
\item \textbf{Non-associative:}
$({}^{\underline{2}}\underline{2})
\uparrow\uparrow \underline{2}
= {}^{\underline{2}}\underline{4} = \underline{256}
\neq \underline{65536}
= {}^{\underline{4}}\underline{2}
= {}^{({}^{\underline{2}}\underline{2})}\underline{2}$.
\item \textbf{No left identity $\geq \underline{2}$:}
for any $\underline{e} \geq \underline{2}$,
${}^{\underline{2}}\underline{e} = \underline{e}^{\underline{e}}
\geq \underline{4} > \underline{2}$.
\end{enumerate}
By contrast, addition has identity~$\underline{0}$,
multiplication has identity~$\underline{1}$,
and exponentiation has right identity~$\underline{1}$
($\underline{n}^{\underline{1}} = \underline{n}$).
The algebraic degradation at level~3
is an independent obstruction to extending
the canonical operation hierarchy beyond tetration.
Proof / Justification
Items (1) and (2) are verified by computation
on small concrete values.
For (3): if $\underline{e} \geq \underline{2}$,
then $\underline{e}^{\underline{e}} \geq \underline{2}^{\underline{2}}
= \underline{4} > \underline{2}$,
so ${}^{\underline{2}}\underline{e}
= \underline{e}^{\underline{e}} \neq \underline{2}$.
Source Context
- Registry source:
book-01.jsonlline 75 - Manuscript source:
2nd-edition/book-i-categorical-foundations/02_mainmatter/part03/ch12-exp-tetration.texlines 368-395
Lean / Formalization Notes
- Formalization:
formalized - Module:
TauLib.BookI.Orbit.Saturation - Name:
Tau.Orbit.Saturation.tetration_algebraic_degradation
Dependencies
- Canonical: I.T02
Related Results
Generated by later projection phases.
Related Publications
Generated by later projection phases.
Revision Notes
- 2026-04-24: Initial pilot migration.
Identifiers
Aliases & legacy IDs
I.T11ctetration-algebraic-degradationthm:tetration-degradedRelease lines
corpus_v3_workingcorpus_v2Relations
Appears in (1)
Sources
Version & History
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